Ziege wrote:I think you will run into too greater losses kw/torque wise, these direct mechanical losses are inalienable as you need some sort of "resistance" to induce a current.
Example, -
the alternator on your car makes energy in gross excess to the electrical needs of your vehicle, the amount of watts per energy at set amperage is way more than you would need, however the fuel source is not used efficiently by either the engine or the alternator, and the heat and other energy losses due to mechanical drag and friction are completely negligible because the exercise is making power, not looking for a certain yield of efficiency, likewise alternators HP/Kw scavenging isn't really factored into the overall energy/fuel consumption due to the necessity of its being there and the fraction of a percent difference it makes vs the losses of efficiency from the drive train and engine itself far outweigh it...
this is the inverse of your hypothetical situation, you would be looking to have as much efficiency vs output of your generator/alternator to yield the greatest return from your finite storage. however there is the inevitability that you will have multiple points of resistance and therefore thermal and kinetic losses from the overall potential, remembering that the energy it took to put it up in the top tank will never be yielded on return, Lets say its a 12v system so it takes (not anywhere near the real figure) 3kw of energy to fill that tank, my assumption if you use most conventional methods of generation you might yield 2kw of power in return due to the 30 something % loss you would likely incur trying to regenerate electrical energy..
Reason? you have multiple forms of energy, kinetic (the one you're trying to harness), Gravitational (a constant therefore a limiter to velocity/torque), Thermal (energy spent and converted due to the endothermic nature of friction)... now gravity as a source of propulsion is advantageous as its automatically a part of your system, however on the fill process its same value is a direct negative on your final energy gains, so this energy you discount from the get go. Kinetic energy or the force put onto the impeller or turbine is your only source of energy with the latter two being either neutral or a negative draw on your overall production. Given this, you would seek to make a generator/alternator that requires the least amount of both frictional and electromagnetic hindrance per kw/h, however I suggest that such generators/alternators would be low output as I dont see small light units producing the 1000's of watts of energy required to run household appliances, you could harness that energy I suppose but you would be in an immediate diminished return than if you had just resorted to battery storage in the first place.
this is without factoring in other issues like changes in environmental temperature and the losses of current from wiring and so on.
The other issue is that you have limitations on what water can provide without considerable mass, acceleration and thusly the velocity of the water is limited by factors such as the diameter of the piping not only out from the tank but into the lower tank, and that water cannot essentially be compressed so its flow per mass is going to be the same over the vanes of the impeller regardless.
Where would be the multiple sources of resistance and losses? Given the water would be cascading almost straight downwards towards a small impeller - maybe 2 impellers - from a height of at least 3m, the only resistance from production side would be at the generator and then losses from cabling ? Where would the mechanical losses be ?
I understand your concerns re torque vs diameter - but the thought I had in my head at least, would be the impellers would sit in a vertical position - cups if you will, spliced into an open section of 1” pipe - this cuts down water requirements and with a 3m head - increases weight / torque significantly. Very roughly - this might spin an impeller at at least a thousand rpms - roughly - and of course design would be paramount. Having it sit vertical resolves many current problems.
How much wind do you need to create 1000w from a wind turbine - 2metres per second...so effectively, you need water to at least replicate that and given water is an actual substance not a gas, you’d need far less of it.
Of course the up hill aspect - solar excess driving a dc pump to move water in daylight hours - that’s actually something I have in place right now...but I’m charging a battery direct rather than using excess power because it was available at the time - but it’s free power regardless...
And yes farmer Pete, your correct. That could work as well.
- good thinking.